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12x^2+76x+80=0
a = 12; b = 76; c = +80;
Δ = b2-4ac
Δ = 762-4·12·80
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-44}{2*12}=\frac{-120}{24} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+44}{2*12}=\frac{-32}{24} =-1+1/3 $
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